How do you differentiate #f(x) = sin (cos(3x -2)) #?

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Answer 1 · 2018-05-25T13:30:03

#f'(x)=-3cos(cos(3x-2))sin(3x-2)#

#f(x) = sin (cos(3x -2))#

Differentiate,

#f'(x)=cos(cos(3x-2))(d/dx(cos(3x-2)))#

Differentiate,

#f'(x)=cos(cos(3x-2))(-sin(3x-2))(d/dx(3x-2))#

Differentiate,

#f'(x)=cos(cos(3x-2))(-sin(3x-2))(3)#

Simplify,

#f'(x)=-3cos(cos(3x-2))sin(3x-2)#