How do you differentiate f(x)=tanx+cotx?

1 Answer
Sep 26, 2016

dy/dx = sec^(2)x+(-csc^(2)x)

Explanation:

The derivative is distributive over addition and subtraction.

Hence:

dy/dx = D_x[tanx] + D_x[cotx]

Differentiating we get:

dy/dx = sec^(2)x+(-csc^(2)x)

It is important to know the derivatives of the trigonometric functions.