Question

How do you differentiate `f(x) = tanx*(x + sec x)`?

Answer 1

`dy/dx=tanx(1+secxtanx)+sec^2x(x+secx)`

Explanation:

Using the product rule we find that the derivative of `y=uv` is `dy/dx=uv'+vu'`

`u=tanx`
`u'=sec^2x`

`v=x+secx`
`v'=1+secxtanx`

`dy/dx=tanx(1+secxtanx)+sec^2x(x+secx)`