How do you differentiate #g(t) = sqrt (t) + 4sec(t)#?

1 Answer
Jim H
Aug 23, 2015

Use the sum rule and the derivatives of #sqrtt# and #sect#.

Explanation:

The derivative os a sum is the sum of the derivatives, so we differentiate term by term.

The first term #sqrtt# has derivative #1/(2sqrtt)# (Use the power rule)

The second term #sect# has derivative #sect tant#

So #g'(t) = 1/(2sqrtt) +sect tant#

Related questions
See all questions in Derivatives of y=sec(x), y=cot(x), y= csc(x)
Impact of this question
1330 views around the world
You can reuse this answer
Creative Commons License