# How do you differentiate g(x) = (6x+9)(5x^6 - 4) using the product rule?

$g ' \left(x\right) = 210 {x}^{6} + 270 {x}^{5} - 24$

#### Explanation:

Given that

$g \left(x\right) = \left(6 x + 9\right) \left(5 {x}^{6} - 4\right)$

$\setminus \frac{d}{\mathrm{dx}} g \left(x\right) = \setminus \frac{d}{\mathrm{dx}} \left(6 x + 9\right) \left(5 {x}^{6} - 4\right)$

$g ' \left(x\right) = \left(6 x + 9\right) \setminus \frac{d}{\mathrm{dx}} \left(5 {x}^{6} - 4\right) + \left(5 {x}^{6} - 4\right) \setminus \frac{d}{\mathrm{dx}} \left(6 x + 9\right)$

$g ' \left(x\right) = \left(6 x + 9\right) \left(30 {x}^{5}\right) + \left(5 {x}^{6} - 4\right) \left(6\right)$

$g ' \left(x\right) = 210 {x}^{6} + 270 {x}^{5} - 24$