How do you differentiate $g(x) =sec^2 x + tan^2 x$ ?

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Answer 1 · 2016-03-06T15:26:19

$d/(d x)g(x)=4 tan x sec^2 x$

$d/(d x)g(x)=2 sec x tan x sec x+2 tan x sec^2x$
$d/(d x)g(x)=2tan x sec^2 x+2 tan x sec^2 x$
$d/(d x)g(x)=4 tan x sec^2 x$

How do you differentiate g(x) =sec^2 x + tan^2 x g(x) =sec^2 x + tan^2 x ?