Question

How do you differentiate `g(x) = sqrt(x-3)tanx` using the product rule?

Answer 1

`f=sqrt(x-3), g=tanx,f'=1/(2sqrt(x-3)) , g'=sec^2x`
`g'(x)=fg'+gf'=sqrt(x-3) sec^2x+tanx/(2sqrt(x-3)`

Explanation:

Separate the products into f and g, find their derivatives and plug everything in to the product rule and simplify