How do you differentiate #g(x) =(x+2)^2 (2x)# using the product rule?
1 Answer
Sep 16, 2016
#dy/dx=6x^2+16x+8#
Explanation:
Given -
#y=(x+2)^2(2x)#
#dy/dx=[(x+2)^2(2)]+[2x .2(x+2) .1]#
#dy/dx=2(x+2)^2+4x(x+2)#
#dy/dx=2(x+2)^2+4x^2+8x#
#dy/dx=2(x^2+4x+4)+4x^2+8x#
#dy/dx=2x^2+8x+8+4x^2+8x#
#dy/dx=6x^2+16x+8#
