Question

How do you differentiate `g(x) = x^3sqrt(2x+1)` using the product rule?

Answer 1

`g'(x)=x^3/[sqrt(2x+1)]+3x^2*sqrt(2x+1)`

Explanation:

show below:

`g(x) = x^3sqrt(2x+1)`

`g'(x)=x^3*2/[2sqrt(2x+1)]+sqrt(2x+1)*3x^2`

`g'(x)=x^3/[sqrt(2x+1)]+3x^2*sqrt(2x+1)`