How do you differentiate #g(y) =(3x-5) ( x^2 - 1) # using the product rule?

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Answer 1 · 2017-04-16T01:09:12

#g'(y)=9x^2-10x-3#

However, using product rule:

#g'(y)=(3x-5)(2x)+(x^2-1)(3)#

Distribute:

#g'(y)=6x^2-10x+3x^2-3#

Simplify:

#g'(y)=9x^2-10x-3#

Note: You can also distribute and use the power rule instead.