Question

How do you differentiate `g(z) = z^3sin(2z)` using the product rule?

Answer 1

`g' (z)=2z^3*cos(2z)+3z^2*sin(2z)`

Explanation:

Differentiate with respect to `z`

`g(z)=z^3*sin(2z)`

`g' (z)=z^3*d/dzsin(2z)+sin(2z)*d/dz(z^3)`

`g' (z)=z^3*2cos(2z)+sin(2z)*3z^2`

`g' (z)=2z^3*cos(2z)+3z^2*sin(2z)`

God bless....I hope the explanation is useful.