How do you differentiate #x^(6x)#? Calculus Differentiating Exponential Functions Differentiating Exponential Functions with Other Bases 1 Answer Konstantinos Michailidis May 16, 2016 You can write this as #x^(6*x)=e^(6x*lnx)# Hence #d(x^(6x))/dx=d(e^(6x*lnx)/dx)=e^(6x*lnx)*(6*lnx+6)= 6*x^(6x)*(lnx+1)# Answer link Related questions How do I find #f'(x)# for #f(x)=5^x# ? How do I find #f'(x)# for #f(x)=3^-x# ? How do I find #f'(x)# for #f(x)=x^2*10^(2x)# ? How do I find #f'(x)# for #f(x)=4^sqrt(x)# ? What is the derivative of #f(x)=b^x# ? What is the derivative of 10^x? How do you find the derivative of #x^(2x)#? How do you find the derivative of #f(x)=pi^cosx#? How do you find the derivative of #y=(sinx)^(x^3)#? How do you find the derivative of #y=ln(1+e^(2x))#? See all questions in Differentiating Exponential Functions with Other Bases Impact of this question 5508 views around the world You can reuse this answer Creative Commons License