Question

How do you differentiate `y = 10^(1-x^2)`?

Answer 1

`y' = -2x * ln(10) * 10^(1-x^2)`

Explanation:

`y = 10^(1-x^2)`
`ln y = (1-x^2)ln(10)`
`1/y \ y' = -2x * ln(10)`
`y' = -2x * ln(10) * 10^(1-x^2)`