How do you differentiate #y=2^x?

1 Answer
Sep 25, 2016

The answer is dy/dx[f'(x)]=2^x ln 2.


According to chain rule, differentiation of 2^x would be 2^x and the natural log of the base is multiplied to it. You can also take log on both sides and apply log rule to change base for obtaining the answer. The second method would be easier for those who have difficulty in performing chain rule.