How do you differentiate #y=ln(e^-x + xe^-x)#? Calculus Differentiating Exponential Functions Differentiating Exponential Functions with Other Bases 1 Answer t0hierry Apr 23, 2016 #y' = -x/(1+x)# Explanation: Write y = ln f then y' = f'/f #f' = - x e^-x # #y' = -x/(1+x)# Answer link Related questions How do I find #f'(x)# for #f(x)=5^x# ? How do I find #f'(x)# for #f(x)=3^-x# ? How do I find #f'(x)# for #f(x)=x^2*10^(2x)# ? How do I find #f'(x)# for #f(x)=4^sqrt(x)# ? What is the derivative of #f(x)=b^x# ? What is the derivative of 10^x? How do you find the derivative of #x^(2x)#? How do you find the derivative of #f(x)=pi^cosx#? How do you find the derivative of #y=(sinx)^(x^3)#? How do you find the derivative of #y=ln(1+e^(2x))#? See all questions in Differentiating Exponential Functions with Other Bases Impact of this question 5790 views around the world You can reuse this answer Creative Commons License