Question

How do you differentiate `y=sin^-1(-2x^2)`?

Answer 1

`(-4x)/sqrt(1-4x^4)`

Explanation:

`d/dx(arcsin(-2x^2))`

`=1/sqrt(1-(-2x^2)^2)*d/dx(-2x^2)`
(arcsin derivative and chain rule)

`=1/sqrt(1-4x^4)*(-4x)`

`=(-4x)/sqrt(1-4x^4)`