How do you differentiate #y=sin^-1(x/3)#?

1 Answer
Nov 23, 2016

#1/sqrt(9-x^2)#

Explanation:

differentiate using the #color(blue)"chain rule"#

#color(orange)"Reminder " color(red)(bar(ul(|color(white)(2/2)color(black)(d/dx(sin^-1(f(x)))=1/(sqrt(1-f(x)^2)).d/dx(f(x)))color(white)(2/2)|)))#

#rArrdy/dx=1/(sqrt(1-(x/3)^2)).d/dx(1/3x)#

#=1/(sqrt(1-x^2/9))xx1/3=1/(3sqrt(1/9(9-x^2)#

#=1/sqrt(9-x^2)#