Question

How do you differentiate `y=sin x^2`?

Answer 1

`dy/dx=2xcos(x^2)`

Explanation:

`y = sin(x^2)`

Applying the chain rule:

`dy/dx= cos(x^2) * d/dx(x^2)`

`= cos(x^2) * 2x` [Power rule]

`= 2xcos(x^2)`