Question

How do you differentiate `y = tan(x + sec x)`?

Answer 1

Use the Chain Rule, together with the derivatives of tangent and secant.

`y = tan(x + sec x)`

`dy/dx = sec^2(x+secx) [d/dx(x+secx)]`

`color(white)"sss"` `= sec^2(x+secx) [1+secxtanx]`

You could write the answer:

`dy/dx = (1+secxtanx)sec^2(x+secx)`