Question

How do you differentiate `y=x^2(sin^-1x)^3`?

Answer 1

Below

Explanation:

`y=x^2((sinx)^(-1))^3`

`(dy)/(dx)=x^2*3((sinx)^(-1))^2*1/sqrt(1-x^2)+2x*((sinx)^(-1))^3`

`(dy)/(dx)=(3x^2((sinx)^(-1))^2)/sqrt(1-x^2)+2x((sinx)^(-1))^3`