Question

How do you differentiate `y=x/(2-tanx)`?

Answer 1

`(2-tanx+xsec^2x)/(2-tanx)^2`

Explanation:

`y=x/(2-tanx)`
`color(red)(d/(dx)(u/v)=(v(du)/(dx)-u(dv)/(dx))/v^2)`
So,
`(dy)/(dx)=((2-tanx)*1-x(-sec^2x))/(2-tanx)^2=(2-tanx+xsec^2x)/(2-tanx)^2`