How do you differentiate #y=(x^4+3)(-4x^5+5x^4+5)# using the product rule? Calculus Basic Differentiation Rules Product Rule 1 Answer loa Apr 3, 2017 #y'=-4x^3(9x^5-10x^4+15x-20)# Explanation: Denote #f(x)=x^4+3# and #g(x)=-4x^5+5x^4+5# so that #y# is of the form #f.g#. The derivative of #y# with respect to #x# according the product rule is then #f'.g+f.g'#: #y' =f'.g+f.g'# #y'=(4x^3)(-4x^5+5x^4+5)+(x^4+3)(-20x^4+20x^3)# #y'=-16x^8+20x^7+20x^3-20x^8+20x^7-60x^4+60x^3# #y'=-36x^8+40x^7-60x^4+80x^3# #y'=-4x^3(9x^5-10x^4+15x-20)# Answer link Related questions What is the Product Rule for derivatives? How do you apply the product rule repeatedly to find the derivative of #f(x) = (x - 3)(2 - 3x)(5 - x)# ? How do you use the product rule to find the derivative of #y=x^2*sin(x)# ? How do you use the product rule to differentiate #y=cos(x)*sin(x)# ? How do you apply the product rule repeatedly to find the derivative of #f(x) = (x^4 +x)*e^x*tan(x)# ? How do you use the product rule to find the derivative of #y=(x^3+2x)*e^x# ? How do you use the product rule to find the derivative of #y=sqrt(x)*cos(x)# ? How do you use the product rule to find the derivative of #y=(1/x^2-3/x^4)*(x+5x^3)# ? How do you use the product rule to find the derivative of #y=sqrt(x)*e^x# ? How do you use the product rule to find the derivative of #y=x*ln(x)# ? See all questions in Product Rule Impact of this question 2699 views around the world You can reuse this answer Creative Commons License