How do you divide #(1+i)/i - 3/(4-i)#?

1 Answer
Jul 2, 2015

I found: #5/17-20/17i#

Explanation:

To evaluate both fractions you first need to change the denominator into a pure real (manipulating the entire fraction). I would multiply and divide both fractions by a "good" complex number, as for example:
#(1+i)/i*color(red)(-i)/color(red)(-i)-3/(4-i)*(color(blue)(4+i))/(color(blue)(4+i))=#
#=(1-i)/1-(12+3i)/17=(17-17i-12-3i)/17=#
#=5/17-20/17i#