How do you divide #(12x^4-18x^3+36x^2)-:6x^3#?

1 Answer
Mar 25, 2018

#2x+3+6/x#

Explanation:

We're dividing a single term, #6x^3#, into a polynomial, so we can take advantage of the following fact which allows us to effectively divide one term into other terms:

#(a+-b)/c=a/c+-b/c#

So,

#(12x^4-18x^3+36x^2)/(6x^3)=(12x^4)/(6x^3)-(18x^3)/(6x^3)+(36x^2)/(6x^3)#

Now, we begin simplifying. Recall that #x^a/x^b=x^(a-b).#

#2x^(4-3)+3x^(3-3)+6x^(2-3)=2x+3+6x^-1=2x+3+6/x#
(As #x^-a=1/x^a#)