How do you divide #(12x ^ { 7} - 8x ^ { 5} - 20x ^ { 2} ) \div ( - 4x ^ { 2} )#?
1 Answer
Jun 24, 2017
Explanation:
#"divide each term on the numerator by " -4x^2#
#rArr(12x^7)/(-4x^2)-(8x^5)/(-4x^2)-(20x^2)/(-4x^2)#
#=-3x^5+2x^3+5#
