How do you divide #(18x ^ { 6} - 27x ^ { 5} + 15x ) \div 3x#?
1 Answer
Jun 1, 2017
Explanation:
#"divide each term on the numerator by " 3x#
#rArr(18x^6-27x^5+15x)/(3x)#
#=(18x^6)/(3x)-(27x^5)/(3x)+(15x)/(3x)#
#=6x^5-9x^4+5larrcolor(red)" quotient"#
