How do you divide #(2+3i)/(1+2i)#?
1 Answer
Feb 8, 2016
Rationalise the denominator to find:
#(2+3i)/(1+2i)=8/5-1/5i#
Explanation:
Multiply both numerator and denominator by the Complex conjugate
#(2+3i)/(1+2i)=((2+3i)(1-2i))/((1+2i)(1-2i))#
#=(2-4i+3i-6i^2)/(1+4)#
#=(8-i)/5#
#=8/5-1/5i#