How do you divide #(2-3i)(5i) /(2+3i)#?

1 Answer
Daniel L.
Oct 24, 2015

#(2-3i)((5i)/(2+3i))=60-25i#

Explanation:

First step is to multiply #(2-3i)# by #5i#:

#(2-3i)((5i)/(2+3i))=(10i+15)/(2+3i)=(5(3+2i))/(2+3i)#

Next step is to expand the fraction by complex conjugate of the denominator. In this way we get a real number in the denominator.

#(5(3+2i))/(2+3i)=(5(3+2i)(2-3i))/((2+3i)(2-3i))=#

#=(5(12-5i))/(4-3)=60-25i#

Related questions
See all questions in Division of Complex Numbers
Impact of this question
2171 views around the world
You can reuse this answer
Creative Commons License