Question

How do you divide `(-2-9i)/(-2+7i)`?

Answer 1

`-59/53+32/53i`

Explanation:

`(-2-9i)/(-2+7i)=(-2-9i)/(-2+7i) xx(-2-7i)/(-2-7i)`

`={-2(-2-7i)-9i(-2-7i)}/{(-2)^2-(-7i)^2]`

`=(4+14i+18i+63i^2}/{4-(49i^2}`

`={4+32i+63(-1)}/{4-49(-1)}`

`=(32i-59)/53`

`=32/53i-59/53`.