How do you divide #(26-43k-83k^2+9k^3)div(7+9k)# using synthetic division?

1 Answer
Jan 29, 2018

Answer:

#color(green)(9k^2 - 90k + 27 + 5/ (k + (7/9)))#

Explanation:

#(9k^3 - 83k^2-43k+26) / (9k + 7)#

#color(white)()-7/9color(white)(aa)|color(white)(aa)9color(white)(aa)-83color(white)(aa)-43color(white)(aaaaaaa)26#
#color(white)(aaaaaa)|#
#color(white)(aaaaaa)|color(white)(a)darrcolor(white)(aa)-7color(white)(aaaa)70color(white)(aaaaa)-21#
#color(white)(aaaaaa)-----------#

#color(white)(aaaaaaaaaa)9color(white)(aa)-90color(white)(aaaa)27color(white)(aaaaaaaa)5#

Answer : #color(green)(9k^2 - 90k + 27 + 5/ (k + (7/9)))#