How do you divide #(2i) / (1 - i)#?
1 Answer
Jan 21, 2016
1 - i
Explanation:
Multiply numerator and denominator by the complex conjugate
of (1 - i ) which is ( 1 + i ). This ensures the denominator is real.(Remember that :
# i^2 = - 1)#
# ( 2i (1 + i ))/((1 - i )(1 + i )) # ( multiply out brackets- distribute )
=
#( 2i + 2i^2) /(1 - i^2 ) =( 2i - 2)/2 = ( cancel(2) (1 - i ))/cancel(2) #
#rArr( 2i)/(1 - i ) = 1 - i #
