How do you divide #(2sqrt3)/sqrt5#?
1 Answer
Apr 26, 2018
Explanation:
#"multiply numerator/denominator by "sqrt5#
#"note that "sqrtaxxsqrta=a#
#•color(white)(x)sqrtaxxsqrtbhArrsqrt(ab)#
#=(2sqrt3)/sqrt5xxsqrt5/sqrt5=(2sqrt15)/5#
