How do you divide (- 2v ^ { 3} + 10v ^ { 2} - 27) \div ( v - 4)?

1 Answer
Jul 24, 2018

(-2v^3+10v^2-27)/(v-4)=-2v^2+2v+8+5/(v-4)

Explanation:

(-2v^3+10v^2-27)/(v-4)

=(-2v^2(v-4)+2v^2-27)/(v-4)

=(-2v^2(v-4)+2v(v-4)+8v-27)/(v-4)

=(-2v^2(v-4)+2v(v-4)+8(v-4)+5)/(v-4)

=-2v^2+2v+8+5/(v-4)

\0/ here's our answer !