How do you divide #(2x^2+7x-15)div(x+5)# using synthetic division?

1 Answer
Jul 15, 2017

Answer:

#(2x-3)#

Explanation:

You can compare coefficients by seeing a quadratic (#x^2#) divided by a linear (single power of x) will result in a linear factor in the form #(ax+b)#

#2x^2+7x-15 = (x+5)(ax+b)#

If you compare coefficients, #xtimesax# must be #2x^2# so #a=2#

Similarly, #5timesb# must equal #-15# so #b=-3#

I would use algebraic division but I don't know how to do the formatting yet!! I'll update my answer when I find out how to show the 'bus stop method'