# How do you divide 3 /(2sqrt2)?

$\setminus \frac{3}{2 \setminus \sqrt{2}} = \setminus \frac{3}{2 \setminus \sqrt{2}} \setminus \frac{\setminus \sqrt{2}}{\setminus \sqrt{2}} =$
$\setminus \frac{3 \setminus \sqrt{2}}{2 {\left(\setminus \sqrt{2}\right)}^{2}} = \setminus \frac{3 \setminus \sqrt{2}}{2 \cdot 2} = \setminus \frac{3}{4} \setminus \sqrt{2}$