Question

How do you divide `(3n ^ { 3} + 23n ^ { 2} + 26n - 26) \div ( n + 6)`?

Answer 1

`(3n^3+23n^2+26n-26)/(n+6)=3n^2+5n-4-2/(n+6)`.

Explanation:

This is a job for synthetic division!

This means that

`(3n^3+23n^2+26n-26)/(n+6)=3n^2+5n-4-2/(n+6)`.

Another way of saying this is

`3n^3+23n^2+26n-26=(3n^2+5n-4)(n+6)-2`.