How do you divide #(3x^3-7x-4)# by #(x-32)#?

1 Answer
Mar 30, 2017

the quotient#=3x^2-7# and a remainder of #-228#

Explanation:

# color(white)(aaaaaaaaaaaaa)##3x^2-7#
#color(white)(aaaaaaaaaaa)##-------#
#color(white)(aaaaa)x-32##|##3x^3+0-7x-4##color(white) (aaaa)##∣##color(blue)(3x^2-7)#

#color(white)(aaaaaaaaaaaa)##3x^3+0##color(white)#
#color(white)(aaaaaaaaaa)##----#
#color(white)(aaaaaaaaaaaaaaaaa)##0-7x-4#

#color(white)(aaaaaaaaaaaaaaaaaaa)##-7x+224#
#color(white)(aaaaaaaaaaaaaaaaaaaaa)##---#
#color(white)(aaaaaaaaaaaaaaaaaaaaaa)##0-228#

The remainder is #=-228# and the quotient is #=3x^2-7#