How do you divide #(4-8i)/(6-5i)#?

1 Answer
Oct 16, 2016

Answer:

=#64/51-(28i)/51#

Explanation:

To simplify a fraction in complex numbers, you must multiply the numerator and denominator by the conjugate of the denominator
In this case the conjugate is #6+5i#
#(4-8i)/(6-5i)=((4-8i)(6+5i))/((6-5i)(6+5i))=(24+20i-48i+40)/(51)=(64-28i)/51=64/51-(28i)/51#
#(6+5i)(6-5i)=36-25i^2=36+25=51# as #i^2=-1#