How do you divide #(4+i)/(8+9i)#?
1 Answer
Dec 18, 2016
Explanation:
To divide the fraction we multiply the numerator/denominator by the
#color(blue)"complex conjugate"# of the denominator.
#8+9i" has conjugate " 8-9i#
#rArr(4+i)/(8+9i)=((4+i)(8-9i))/((8+9i)(8-9i))# expand numerator/denominator using FOIL method.
#=(32-36i+8i-9i^2)/(64-72i+72i-81i^2)#
#color(orange)"Reminder " i^2=(sqrt(-1))^2=-1#
#=(41-28i)/145=41/145-28/145i#
