Question

How do you divide `(4x^5+3x^3-2x^2)` by `2x`?

Answer 1

`2x^4+3/2x^2-x`

Explanation:

`"divide each term on the numerator by 2x"`

`rArr(4x^5)/(2x)+(3x^3)/(2x)-(2x^2)/(2x)`

`=2x^4+3/2x^2-x`