How do you divide #(5-i)/(3+3i)#?

2 Answers
Jan 11, 2016

Answer:

Multiply top and bottom by the conjugate of the denominator ...

Explanation:

#(5-i)/(3+3i)xx(3-3i)/(3-3i)=(12-18i)/(18)=2/3-i#

hope that helped

Jan 11, 2016

Answer:

Multiply the fraction by 1 (the conjugate of the denominator/the conjugate of the denominator)

Explanation:

#(5-i)/(3+3i)#*#(3-3i)/(3-3i)#=#(12-18i)/(9+9)#=#(1/18)(12-18i)#