How do you divide #(6x ^ { 2} + 45x + 25) \div ( x + 7)#?
1 Answer
Dec 22, 2017
Explanation:
#"one way is to use the divisor as a factor in the numerator"#
#"consider the numerator"#
#color(red)(6x)(x+7)color(magenta)(-42x)+45x+25#
#=color(red)(6x)(x+7)color(red)(+3)(x+7)color(magenta)(-21)+25#
#=color(red)(6x)(x+7)color(red)(+3)(x+7)+4#
#"quotient "=color(red)(6x+3)," remainder "=4#
#rArr(6x^2+45x+25)/(x+7)=6x+3+4/(x+7)#
