How do you divide #(6x ^ { 2} + 7x - 10) \div ( x + 2)#?

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Answer 1 · 2018-01-14T13:41:07

See a solution process below:

First, rewrite the expression as:

#(6x^2 + 7x - 10)/(x + 2)#

We can now factor the numerator as:

#((6x - 5)(x + 2))/(x + 2)#

We can now cancel the common term in the numerator and denominator giving:

#((6x - 5)color(red)(cancel(color(black)((x + 2)))))/color(red)(cancel(color(black)(x + 2))) =>#

#6x - 5#

However, we must remember we cannot divide by #0#, therefore:

#x + 2 != 0#

Or

#x != -2#

The solution is

#6x - 5# where #x != -2#