Question

How do you divide `(6x ^ { 3} - 19x ^ { 2} + 16x - 4) -: ( x - 2)` by synthetic division?

Answer 1

Quotient is `6x^2-7x+2` and remainder is `0`

Explanation:

`6x^3-19x^2+16x-4`

=`6x^3-12x^2-7x^2+14x+2x-4`

=`6x^2*(x-2)-7x*(x-2)+2*(x-2)`

=`(6x^2-7x+2)*(x-2)`

Thus, quotient is `6x^2-7x+2` and remainder is `0`