How do you divide #(9w ^ { 3} + 3w ^ { 2} + w - 12) \div ( 9w )#?

1 Answer
Alan P.
Oct 2, 2017

#(9w^3+3w^2+w-12)div (9w)=color(red)(w^2+w/3+1/9-4/(3w))#

Explanation:

#(9w^3+3w^2+w-12) div (9w)#

#color(white)("XXX")=(color(blue)(9w^3)+color(green)(3w^2)+color(brown)w-color(magenta)(12))/(9w)#

#color(white)("XXX")=color(blue)((9w^3)/(9w))+color(green)((3w^2)/(9w))+color(brown)(w/(9w))-color(magenta)(12/(9w))#

#color(white)("XXX")=color(blue)(w^2)+color(green)(w/3)+color(brown)(1/9)-color(magenta)(4/(3w))#

Related questions
Impact of this question
631 views around the world
You can reuse this answer
Creative Commons License