How do you divide #a/(ib)#?
1 Answer
Jan 22, 2017
Explanation:
#color(orange)"Reminder " color(red)(bar(ul(|color(white)(2/2)color(black)(i^2=(sqrt(-1))^2=-1)color(white)(2/2)|)))# We require to rationalise the denominator.
This is achieved by multiplying the numerator/denominator by i
#a/(bi)xxi/i=(ai)/(bi^2)=(ai)/(-b)=-a/bi#