Question

How do you divide and rationalize `sqrt24/sqrt3`?

Answer 1

Working this out gives `2sqrt(2)`
How, you ask
`sqrt(24)/sqrt(3) = sqrt(24/3)`
`= sqrt(8)`
`= sqrt(2xx4)`

Note that : `2xx4 = 8`

`= sqrt(2)xxsqrt(4)`
YES: `sqrt(2xx4) = sqrt(2)xxsqrt(4)`
`=> sqrt(2)xx2`
`=> 2sqrt(2)`