# How do you divide and rationalize the denominator for 2/(sqrt3+sqrt2)?

You can multiply and divide by $\sqrt{3} - \sqrt{2}$ to get:
2/(sqrt(3)+sqrt(2))×(sqrt(3)-sqrt(2))/(sqrt(3)-sqrt(2))=(2sqrt(3)-2sqrt(2))/(3-2)=
$= 2 \sqrt{3} - 2 \sqrt{2}$