Question

How do you divide and rationalize the denominator for `2/(sqrt3+sqrt2)`?

Answer 1

You can multiply and divide by `sqrt(3)-sqrt(2)` to get:
`2/(sqrt(3)+sqrt(2))×(sqrt(3)-sqrt(2))/(sqrt(3)-sqrt(2))=(2sqrt(3)-2sqrt(2))/(3-2)=`
`=2sqrt(3)-2sqrt(2)`