# How do you divide and simplify the square root of (sqrt(96x^3))/(sqrt(25y^6))?

$\frac{\sqrt{96 {x}^{3}}}{\sqrt{25 {y}^{6}}} = \frac{\sqrt{6 \cdot {4}^{2} \cdot x \cdot {x}^{2}}}{\sqrt{{5}^{2} \cdot {\left({y}^{3}\right)}^{2}}}$
$= \frac{4 \cdot x \cdot \sqrt{6 \cdot x}}{5 \cdot {y}^{3}} = \frac{4}{5} \cdot \frac{x \sqrt{6 x}}{{y}^{3}}$