How do you divide #\frac { 1- 9y ^ { 2} } { y ^ { 2} - 25} \div \frac { y ^ { 2} - 3y - 10} { 3y ^ { 2} + 5y - 2}#?

1 Answer
sahar del
Mar 3, 2018

#(-((3y+1)(3y-1)(3y-1)))/((y+5)(y-5)(y-5))#

Explanation:

#((1-9y^2)/(y^2-25) ). (3y^2+5y-2)/(y^2-3y-10)#

#(-(9y^2+1))/(y^2-25) . (3y^2+5y-2)/(y^2-3y-10)#

#-((3y+1)(3y-1))/((y+5)(y-5)).(3y^2+5y-2)/((y+2)(y-5))#

#-((3y+1)(3y-1))/((y+5)(y-5)).(3y-1)/(y-5)#

#(-((3y+1)(3y-1)(3y-1)))/((y+5)(y-5)(y-5))#

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